Factors

# Factors of 20 | Prime Factorization of 20 | Factor Tree of 20

Written by Prerit Jain

Updated on: 08 Jun 2023

Contents

### Factors of 20 | Prime Factorization of 20 | Factor Tree of 20

## Factors of 20

Factors of 20 | Factor Pairs of 20 | Prime factors of 20 |

1, 2, 4, 5, 10, 20 | (1,20) (2,10) (4,5) (5,4) (10,2) | 2 x 2 x 5 |

**Factors of 20**,

**Factor Pairs of 20**,

**Prime factors of 20**

Calculate Factors of

**The Factors are**

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## What are the factors of 20

To find the factors of 20, you can follow these steps:

1. Begin by writing down the number 20.

2. Divide 20 by all the integers from 1 to 20 to find the factors.

3. If the remainder is 0 for any of these divisions, then the corresponding numbers are factors of 20.

For example, when we divide 20 by 1, we get a quotient of 20 and a remainder of 0. This means that 1 is a factor of 20. When we divide 20 by 2, we get a quotient of 10 and a remainder of 0. This means that 2 is a factor of 20. And so on.

**The complete list of factors of 20 is 1, 2, 4, 5, 10, 20**

Alternatively, you can use the multiplication method to find the factors of 20. To do this, start by writing down the number 20 and then list all the pairs of numbers that can be multiplied together to equal 20. The factors of 20 using the multiplication method are: (1, 20), (2, 10), (4, 5), (5, 4), (10, 2), (20, 1)

Note that the order in which the numbers appear in the pair does not matter, so (1, 20) and (20, 1) are considered the same pair.

## How to Find Factors of 20

To find the factors of 20, you can use one of the following methods:

Here are four methods that you can use to find the factors of 20:

- Factors of 20 using the Multiplication Method
- Factors of 20 using the Division Method
- Prime Factorization of 20
- Factor tree of 20

## Factors of 20 using the Multiplication Method

To find the factors of 20 through multiplication, follow these steps:

- Start by writing down the number 20.
- Determine all the pairs of numbers that can be multiplied to get 20.
- The factors of 20 using the multiplication method are (1, 20), (2, 10), (4, 5), (5, 4), (10, 2), (20, 1).

Remember, the order of the numbers in the pairs does not matter, so (1, 20) and (20, 1) are considered the same pair.

## Factors of 20 using the Division Method

To find the factors of 20 using division, follow these steps:

- Start by writing down the number 20.
- Divide 20 by each integer from 1 to 20.
- If the remainder is 0 for any of these divisions, then the corresponding number is a factor of 20.

For example, dividing 20 by 1 results in a quotient of 20 and a remainder of 0, so 1 is a factor of 20. Dividing 20 by 2 gives a quotient of 10 and a remainder of 0, so 2 is a factor of 20. This process can be continued until all the factors of 20 are found.

**Using the division method, the complete list of factors of 20 is 1, 2, 4, 5, 10, 20.**

## Prime Factorization of 20

Calculate Prime Factors of

The Prime Factors of 20 =

2 x

2 x

5

**The prime factorization of 20 is 2 x 2 x 5.**

To find the prime factorization of a number, you need to find the prime numbers that can be multiplied together to give the original number. For example, the prime factorization of 20 is 2 x 2 x 5, because 2 and 5 are prime numbers and 20 can be expressed as the product of two 2s and one 5 (2 x 2 x 5 = 20).

The prime factorization of a number is written as the product of its prime factors. For example, the prime factorization of 20 is written as 2 x 2 x 5.

## Factor tree of 20

To determine the prime factorization of 20 using a factor tree, follow these steps:

- Begin by writing down the number 20.
- Identify the smallest prime factor of 20. The smallest prime factor of 20 is 2.
- Draw a branch from the number 20 and write the prime factor (2) on the branch.
- Divide the number 20 by 2 to get 10.
- Identify the smallest prime factor of 10. The smallest prime factor of 10 is 2.
- Draw a branch from the number 10 and write the prime factor (2) on the branch.
- Divide the number 10 by 2 to get 5.
- Identify the smallest prime factor of 5. The smallest prime factor of 5 is 5 itself since it is already a prime number.
- Draw a branch from the number 5 and write the prime factor (5) on the branch.
- The prime factorization of 20 is now complete, so the factor tree is done.

## Factor Pairs of 20

Calculate Pair Factors of

1 x 20=20

2 x 10=20

4 x 5=20

5 x 4=20

10 x 2=20

So Pair Factors of 20 are

(1,20)

(2,10)

(4,5)

(5,4)

(10,2)

To find the pairs of numbers that multiply together to equal 20, you can follow these steps:

- Begin by writing down the number 20.
- Identify all the pairs of numbers that can be multiplied together to equal 20.
- The factor pairs of 20 are (1, 20), (2, 10), (4, 5), (5, 4), (10, 2), (20, 1).

Note that the order of the numbers in each pair does not matter, so (1, 20) and (20, 1) are considered the same pair.

## Factors of 20 – Quick Recap

**Factors of 20:**1, 2, 4, 5, 10, 20.**Negative Factors of 20:**-1, -2, -4, -5, -10, and -20.**Prime Factors of 20:**2 × 2 × 5**Prime Factorization of 20:**2 × 2 × 5

## Factors of 20 – Fun Facts

- The factors of 20 include both even and odd numbers.
- 20 is a composite number, which means it has more than two factors.
- The prime factorization of 20 is 2 x 2 x 5.
- The sum of the factors of 20 is 32.
- The product of the factors of 20 is 160.
- The only even perfect square that is a factor of 20 is 4.
- The smallest factor of 20 is 1, and the largest factor is 20.
- 20 is divisible by all its factors. For example, 20 is divisible by 1, 2, 4, 5, and 10.
- The number of factors of 20 is 6.
- 20 is a multiple of both 2 and 10.

Also Check: Multiples, Square Root, and LCM

## Solved Examples of Factor of 20

**Q.1:What is the greatest common factor (GCF) of 20?****Answer: **The greatest common factor (GCF) of 20 is 4; it’s the largest number by which both can be divided without a remainder.

**Q.2:** How many factors does twenty have?**Solution: **Twenty has six different factors; these include 1, 2, 4, 5, 10, and 20.

** Q.3: Find three prime numbers whose product equals forty when multiplied together.Solution: **Three prime numbers whose product equals forty when multiplied together are 2, 3, and 5; 2x3x5= 40.

** Q.3:** I

**s 18 a multiple or a**

**factor of 20?**

18 is a multiple but not a factor of twenty as it cannot be divided evenly with no remainder (18/20 = 0.9).

**Solution:**** Q.4: Ashley needs to divide an equation into equal parts however each part must be divisible by four; what equation could she use?Solution: **Ashley could use 16×8=128 as this equation can be divided into two equal parts both divisible by four (128/4 = 32 & 128/32 = 4).

** Q.5: How many odd numbers remain between 1-20 when all even numbers are removed?Solution: **Nine odd numbers remain between one and twenty when all even numbers are removed; these would include 1, 3, 5, 7, 9, 11, 13, 15, and 19.

** Q.6: Find two prime numbers that can only be divided evenly by themselves and one to generate a product that totals sixteen.Solution: **Two prime numbers that can only be divided evenly by themselves and one to generate a product that totals sixteen are 2 and 8; 2×8=16 and neither can be divided evenly with another number apart from themselves or one in order to equal sixteen.

** Q.7: If there are five unequal numbers multiplied together which is the greatest possible total if their product equals thirty-two?Solution: **The greatest possible total if five unequal numbers multiplied together equal thirty-two is 6; 1x2x4x8x6= 32.

**Q.8:** How many pairs of factors are needed in order to multiply together in order to generate sixty-four?** Solution:** Two pairs of factors need multiplying together in order to generate sixty-four; these would include 8×8=64 & 4×16=64.

** Q.9: What two consecutive odd numbers add up to fourteen while their product remains divisible by five?Solution:** Two consecutive odd numbers adding up to fourteen while keeping their product divisible by five are 7 & 9 (7+9 = 16 & 7×9 = 63); 63/5 = 12.

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## Frequently Asked Questions on Factors of 20

**What is the greatest common factor (GCF) of 20?**

The greatest common factor (GCF) of 20 is 4; it’s the largest number by which both can be divided without a remainder.

**How many factors does twenty have?**

Twenty has six different factors; these include 1, 2, 4, 5, 10, and 20.

**How many odd numbers remain between 1-20 when all even numbers are removed?**

Nine odd numbers remain between one and twenty when all even numbers are removed; these would include 1, 3, 5, 7, 9, 11, 13, 15, and 19.

**Find two prime numbers that can only be divided evenly by themselves and one to generate a product that totals sixteen.**

Two prime numbers that can only be divided evenly by themselves and one to generate a product that totals sixteen are 2 and 8; 2×8=16 and neither can be divided evenly with another number apart from themselves or one in order to equal sixteen.

**If there are five unequal numbers multiplied together which is the greatest possible total if their product equals thirty-two?**

The greatest possible total if five unequal numbers multiplied together equal thirty-two is 6; 1x2x4x8x6= 32.

**Is 18 a multiple or a factor of 20?**

18 is a multiple but not a factor of twenty as it cannot be divided evenly with no remainder (18/20 = 0.9).

**How many pairs of factors are needed in order to multiply together in order to generate sixty-four?**

Two pairs of factors need multiplying together in order to generate sixty-four; these would include 8×8=64 & 4×16=64.

**Find three prime numbers which multiplied together and **generate a product that is divisible by five.

Three prime numbers multiplied together to generate a product that is divisible by five are 3, 5, and 7; 3x5x7= 105 and 105/5= 21.

**Danny needs to reduce an equation by half but keep it divisible by five; what equation could he use?**

Danny could use 10×2=20 as this equation can be reduced by half while still staying divisible by five (10/2=5 and 20/5=4).

**What two consecutive odd numbers add up to fourteen while their product remains divisible by five?**

Two consecutive odd numbers adding up to fourteen while keeping their product divisible by five are 7 & 9 (7+9 = 16 & 7×9 = 63); 63/5 = 12.

Written by by

Prerit Jain