Factors of 158 | Prime Factorization of 158 | Factor Tree of 158

Factors of 158

Factors of 158	Factor Pairs of 158	Prime factors of 158
1, 2, 79, 158	(1, 158), (2, 79)	2 x 79

Looking to Learn Math? Explore Wiingy’s Online Math Tutoring Services to learn from top mathematicians and experts.

What are the factors of 158

People often are puzzled when they hear the words “factors” and “factorization”, but it’s actually quite simple. A factor of a number is any integer (like 1, 2 or 79) that you can multiply together to get the original number – 158 in this case! If we take all these factors out for a spin, there will be 6 altogether: 1 x 158 =158; 2 X 79=158; 4 X 39=156, etc.. But hold on – did you know that not every whole numerical value like this one can have only two numbers as its factors? Yep – if those two numbers happen to both be ‘1’, then guess what kind of number we’ve got here?! That’s right–it’s called a prime number! However, in our case with 158, it doesn’t work—which means we need more than just one pair of integers multiplied by each other (in fact-four pairs!) And since after trying different combinations none gave us back “2×79”, we were able to call our final result —a composite. 

How to Find Factors of 158

The main methods through which we can find the factors of 158 are as follows: 

• Factor of 124 using Multiplication Method
• Factors of 124 using Division Method
• Prime Factorization of 124
• Factor tree of 124

Factors of 158 using Multiplication Method

Let’s use the number 158 to see how the Multiplication Method works. The way this method works is by finding two numbers that when multiplied together equal 158. An example would be 1 and 158, or 2 and 79 which both multiply out to give us exactly 159! So for our number of 158, we have factor pairs (1,158) and (2,79). In other words, if you took one from each pair – like 1 plus 79 – it adds up to get you back your original total of 158 again!

Factors of 158 Using Division Method

Have you ever wondered what the factors of a number are? Factors are special numbers that can be multiplied together to create other numbers. For example, if we multiply 2 and 79, our total is 158! To find all the possible factors for any given number using Division Method, start by dividing it by 1 then move up towards the square root (a special type of number – like 8 or 9) one at a time until there’s no remainder left when divided.

• Let’s try this out with 158 as an example: When we divide 158 by 1 resulting in nothing left over; so 1 is a factor. 
• Divide again with 2 leading us to nothing remaining so two also must be assumed as a factor- the same goes on till reaching sqrt(158). 
• This way eventually will tell us four different numbers which have been served by multiplying them –it gives us:  1 x2x79x158= 159!

Prime Factorization of 158

Have you ever wondered how to find out the prime numbers that make up any given number? When it comes to understanding the prime factorization of 158, this is a process where we can break down one large number into smaller ones. Let’s say for example your teacher gave you the number 158 and asked “what are all its component parts?” To answer this question, first, take a look at 2 – remember when it comes to reviewing primes; these are always divisible by themselves only! – See if dividing two will result in an even remainder: in other words divide 158 /2 = 79 – since there is not another whole fraction here (the quotient), then use ‘2’ as our starting point with solving 159s components. By doing so ‘158’, becomes equal to 2×79!  So there you have it- The Prime Factorization Of 168 is simply made up of just two primes which multiplied together equals our sought-after total amount: 2 x 79 = 148. 

Factor tree of 158

Factor trees are a fun and helpful way to find the prime factorization of any number. For example, if you wanted to figure out what 158 can be broken down into, here’s how:

First write 158 at the top of your tree. Then draw two branches coming off from it and on each branch write one number that evenly divides into 158 – which is 2 & 79! Now since 79 is already a Prime Number (meaning only itself will divide into it) then there’s nothing more we need to do for this side! So altogether our Factor Tree looks like this… 

             158  

           /     \  

          2        79   

This means our result is…158 =2 x79

Factor Pairs of 158

To find the factor pairs of 158, we can break it into smaller steps. First, divide 158 by each number from 1 to the square root of that same number (in this case, 12.64). If when you do so there is no remainder left over then that pair is a factor! An example would be if you divided 158 by 2 – it will give 79 as an answer and 0 for a remainder meaning (2,79) is one set of factors for 158. And even though these two numbers are reversed like in with (79,2), they still count because all sets show how 158 can be broken down into other whole numbers! The three distinct factor pairs for 158 are: (1, 158),(2, 79 ), and(79, 2 ).

Factors of 158 – Quick Recap

Factors of 158:  1, 2, 79, 158

Negative Factors of 158:  -1, -2, -79, -158.

Prime Factors of 158: 2 x 79

Prime Factorization of 158: 2 x 79

Fun Facts of Factors of 158

• 158 is a very special number! It has something called “prime factorization” which means that it can be written as the product of two or more prime numbers. For example, 158 equals 2×79 – and no matter how you combine those primes together to get 158, it will always equal the same amount! 

• 158 also has 6 factors in total: 1 (which we call “unit”), 2, 79,158 itself plus one extra 158 so altogether 558. The sum of all these factors is known as its ‘aliquot sum’ which makes 240 – this figure must always be larger than our original number. 

Examples of Factor of 158

1) Emma had 158 pencils and wanted to divide them into 6 groups with the same number of pencils in each group. How many pencils would there be in each group?
Answer: Each group would have 26 pencils (158 ÷ 6 = 26).

2) Sarah was given 158 coins as a gift. She found out that the coins were composed of one-dollar coins, fifty-cent coins, and twenty-five-cent coins. If she had an equal number of each type of coin, how many coins of each did Sarah have?
Answer: Sarah had 52 one-dollar coins, 52 fifty-cent coins and 54 twenty-five cent coins ((158÷3=52)+(52×2=104)).

3) Susan has 158 apples and wants to divide them into 8 groups with the same number in each group. How many apples would there be in each group?
Answer: Each group would have 19 apples (158÷8=19).

4) David needs to buy 158 boxes of chocolates for his store. He knows that they come in packs of 5 and 7. What is the greatest number he can buy with packs of both sizes?
Answer: David can buy 71 boxes with packs of both sizes ((22×7=154)+ (4×5=20)=174).

5) There are 158 students in the school. If there are 4 classrooms with 39 students in each, how many students per classroom would there be?
Answer: There would be 39 students per classroom (158÷4=39).

6) Mark wanted to cut a piece from a cake that weighed 158 grams so that it weighed half as much as before. How much would the piece weigh after it was cut?
Answer: The piece after cutting would weigh 79 grams (158/2 = 79).

7) Rachel had 158 berries and needed to distribute them evenly among 11 jars. How many berries should go into each jar?
Answer: Each jar should contain 14 berries(158÷11 =14). 

8) Paul caught 158 fish during his fishing trip and wants to give away 16 fish at the end of the day but keep 4 for himself. How much fish can he give away?
Answer: Paul can give away 112 fish(16×7=112). 

9) Jake collected 58 rocks from the beach but his friend wanted him to bring enough stones so that they divide equally between 6 people including himself. How many stones does Jake need to collect in order to satisfy everyone’s desires?
Answer: Jake needs to collect one hundred and fifty-eight stones (6×26⁣=156+2extra), so he can have 26 stones for each person including himself. 

10) Jeff has a collection of 158 stamps and he wants to divide them into 33 groups with an equal number of stamps in each group, what is the exact number of stamps in every group?
Answer: Every group will contain 4 stamps (158 ÷ 33 = 4).

Looking to Learn Math? Explore Wiingy’s Online Math Tutoring Services to learn from top mathematicians and experts.

Frequently Asked Questions on Factors of 158