Factors

# Factors of 118 | Prime Factorization of 118 | Factor Tree of 118

Written by Prerit Jain

Updated on: 24 Aug 2023

Contents

### Factors of 118 | Prime Factorization of 118 | Factor Tree of 118

## Factors of 118

Factors of 118 | Factor Pairs of 118 | Prime factors of 118 |

1, 2, 59, 118 | (1, 118), (2, 59) | 2 × 59 |

**Factors of 118**,

**Factor Pairs of 118**,

**Prime factors of 118**

Calculate Factors of

**The Factors are**

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## What are the factors of 118

The factors of a given number are the numbers that are capable of dividing the given number uniformly with no decimal points in the quotient. So, for example, the factors of 12 are 1, 2, 3, 4, 6, and 12, as all of these numbers, can evenly divide the given number 12.

To find the factors of 118, we can start by dividing 118 by 2. If 118 is evenly divisible by 2, then 2 is a factor of 118. If 118 is not evenly divisible by 2, then we can try dividing it by 3, and so on.

Here’s how it would work:

- 118 / 2 = 59 (evenly divisible)
- 118 / 3 = 39.33333333333333(not evenly divisible)
- 118 / 4 = 29.5 (not evenly divisible)
- 118 / 5 = 23.6 (not evenly divisible)

We can keep going like this until we find a number that 118 is evenly divisible by. But if we keep going, we will eventually find that 118 is evenly divisible by 1, 2, 59, and 118.

**So, The factors of 118 are 1, 2, 59, and 118.**

## How to Find Factors of 118

The 4 methods through which the factors of a number can be found are as follows and the same methods can be used to find the factors of 118.

- Factors of 118 using the Multiplication Method
- Factors of 118 using the Division Method
- Prime Factorization of 118
- Factor tree of 118

## Factors of 118 Using the Multiplication Method

To find the factors of 118 using the multiplication method, we can look for pairs of numbers that can be multiplied together to get the 118. For example, we know that 1 x 118 is equal to 118, so 1 and 118 are both factors of 118.

We can also look for other pairs of numbers that multiply to give us 118. For example, 2 x 59 is equal to 118, so 2 and 59 are both factors of 118.

**So, in total, the factors of 118 are 1, 2, 59 and 118.**

## Factors of 118 Using the Division Method

To find the factors of 118 using the division method, we can start by trying to divide 118 by different numbers. If 118 is evenly divisible by a number, then that number is a factor of 118.

For example, if we divide 118 by 2, we get 59. This is a whole number, so 2 is a factor of 118. If we divide 118 by 3, we get 39.33333333333333. This is not a whole number, so 3 is not a factor of 118.

We can keep going like this until we find all the factors of 118. Some of the numbers that are factors of 118 are 1, 2,59 and 118. These are all the numbers that we can divide 118 by and get a whole number.

## Prime Factorization of 118

Calculate Prime Factors of

The Prime Factors of 118 =

2 x

59

To find the prime factorization of a number, we try to express it as a product of its prime factors. A prime number is a number that is only divisible by 1 and itself. For example, the first few prime numbers are 2, 3, 5, 7, 11, and 13.

To find the prime factorization of 118, we can start by dividing 118 by the smallest prime number, which is 2. If 118 is evenly divisible by 2, then we can divide it by 2 again and again until we get a number that is not evenly divisible by 2.

For example, if we divide 118 by 2, we get 59. This is evenly divisible by 2, so we can divide it by 2 again to get 29.5. This is not evenly divisible by 2, so we stop here.

If 118 is not evenly divisible by 2, we move on to the next smallest prime number, which is 3. If we divide 118 by 3, we get 39.33333333333333. This is not a whole number, so 3 is not a factor of 118.

We can keep going like this until we find all the prime factors of 118. This means that the prime factors of 118 are 2 and 59, and 2 appears once in the prime factorization.

**In this case, the prime factorization of 118 is 2 x 59**.

## Factor tree of 118

A factor tree is a diagrammatic representation prime factorization of a number. It is called a tree because it has branches that represent the different prime factors of the number.

To create a factor tree for 118, we can start by finding two numbers whose product is 118. For example, we can find that 2 and 59 are both factors of 118 because 2 x 59 = 118.

Next, we can find two numbers whose product is 59. As 59 is a prime number It cannot be further divided into another prime factors.

Finally, we can create a tree-like diagram to represent the factors of 118. The top of the tree would be 118, and the two branches would be 2 and 59.

**This diagram shows that 118 can be expressed as a product of its prime factors: 2 x 59.**

## Factor Pairs of 118

Calculate Pair Factors of

1 x 118=118

2 x 59=118

59 x 2=118

So Pair Factors of 118 are

(1,118)

(2,59)

(59,2)

The factor pairs of a number are all the pairs of numbers that, when multiplied together, give that number. For example, the factor pairs of 12 are (1, 12), (2, 6), and (3, 4), because the product of these pairs is 12.

To find the factor pairs of 118, we can list all the factors of 118, which are 1, 2,59, and 118. Then, we can find all the pairs of these numbers that multiply to give 118.

**Therefore, the factor pairs of 118 are (1, 118), (2, 59).**

## More Factors

- Factors of 115
- Factors of 116
- Factors of 117
- Factors of 118
- Factors of 119
- Factors of 120
- Factors of 121

## Factors of 118 – Quick Recap

**Factors of 118:**1, 2, 59, 118.**Negative Factors of 118:**-1, -2, -59, -118.**Prime Factors of 118:**2 × 29**Prime Factorization of 118:**

**Also Check**: Multiples, Square Root, and LCM

## Solved Examples of Factor of 118

**Q.1: A toy store has 108 teddy bears. How many can each customer buy if there are 12 customers?****Solution: **Each customer can buy 9 teddy bears.

**Q.2: ** There are 116 lemonades in a pitcher, and 4 people want to divide them evenly. How many lemonades will each person get?** Solution: ** Each person will get 29 lemonades.

**Q.3: ** John has 108 marbles in a jar and wants to evenly distribute them among 3 of his friends. How many marbles will each friend get? ** Solution: **Each friend will get 36 marbles.

**Q.4: ** Jimmy has 115 books and wants to give an equal number to 7 of his friends. How many books will each friend receive? ** Solution: **Each friend would receive 15 books in this case.(115/7=15)

**Q.5: ** Jessica wrote 118 questions for her quiz, and wants to divide them between 3 teams equally so that every team gets the same amount of questions for their quiz night challenge – how many questions does each team receive? ** Solution: **Each team will receive 37 questions for the quiz night challenge. (118/3 = 37)

**Q.6: ** There are 118 apples available at the farmer’s market and there are 5 customers wanting some apples – how many apples should each customer receive? ** Solution: **If there are 118 apples available and 5 customers wanting apples, each customer should receive 118 divided by 5, which is approximately 23.6 apples. Since we cannot have a fraction of an apple, it would be more practical for each customer to receive 23 apples, with a remainder of 3 apples left over.

**Q.7: ** Eleanor has 116 markers she wants to evenly distribute among 10 students how many markers will each student get? **Solution: **If Eleanor has 116 markers and wants to distribute them evenly among 10 students, each student would receive 116 divided by 10, which is equal to 11.6 markers. Since we cannot have a fraction of a marker, it would be more practical for each student to receive 11 markers, with a remainder of 6 markers left over.

**Q.8: ** What are the least prime numbers needed to multiply together in order to get 1188? ** Solution: ** To find the least prime numbers needed to multiply together to get 1188, we can start by finding the prime factorization of 1188. Prime factorization of 1188: 1188 = 2^2 * 3^3 * 11. So, the least prime numbers needed to multiply together to get 1188 are 2, 3, and 11.

**Q.9: ** How can I find the greatest common factor between 1190 and 1202? **Solution:** To find the greatest common factor between 1190 and 1202 you need to list out all factors of both numbers from 1 up until you find a number that they both have in common; this number would be your greatest common factor (GCF). In this case, it would be 2.

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## Frequently Asked Questions on Factors of 118

**What are the factors of 118?**

The factors of 118 are 1, 2, 59, and 118.

**Is 118 a prime number?**

No, 118 is not a prime number because it can be divided evenly by more than two numbers (1, 2, 59, and 118).

**What is the greatest common factor between 1180 and 1206?**

The greatest common factor between 1180 and 1206 is 2.

**How can I find the lowest common multiple of 1180 and 1206?**

Prime factorization of 1180: 2^2 * 5 * 59. Prime factorization of 1206: 2 * 3 * 7 * 29. Highest power of 2: 2^2 ,Highest power of 3: 3 , Highest power of 5: 5, Highest power of 7: 7 , Highest power of 29: 29.Multiply the highest powers of each prime factor. 2^2 * 3 * 5 * 7 * 29 = 12180.Therefore, the lowest common multiple (LCM) of 1180 and 1206 is 12180.

**How many coins would each person get if there were an even split among six people of a collection of 114 coins?**

Each person would get 19 coins in this case.

**How many minutes does someone need to read if they have a total of 118 pages with an allotted one minute per page?**

Someone needs to read 118 pages at one minute per page to complete their task.

**What is the least prime number needed to multiply together in order to get 1188?**

Prime factorization of 1188: 2^2 * 3^4 * 11. The least prime number in the prime factorization of 1188 is 2. Therefore, the least prime number needed to multiply together to get 1188 is 2.

**If there are 119 apples how many apples should each person get if they’re split among three people? **

119 apples / 3 people = 39 remainder 2

Each person would receive 39 apples, with 2 apples remaining

**How many customers can buy books if there are 119 books for sale and four customers want to purchase them?**

119 books / 4 customers = 29 remainder 3

Each customer would be able to buy 29 books, with 3 books remaining. So, if the books are divided equally, each customer would be able to buy 29 books. However, if you want to distribute the remaining 3 books, you can give each customer one additional book, resulting in 30 books for each customer and 1 book left over.

Written by by

Prerit Jain