Factors of 131 | Prime Factorization of 131 | Factor Tree of 131

Factors of 131

Factors of 131	Factor Pairs of 131	Prime factors of 131
1, 131	(1, 131)	131

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What are the factors of 131

To find the factors of a number, we can start by dividing it by 1. If there is no remainder (or if the remainder equals 0) then that is one factor! For example, 131 divided by 1 equals 131 with no remainders so this means that 1 and also131 are both factors of our mystery number: 131! To try to see what else could be a factor for our mystery number, let’s divide it nextly in two…so when you take out 131 from 2, how much do you get? You get 65 but with still some leftover — which tells us 2 isn’t quite right as an answer. Next up 3–when you try taking away 132 from three times…it’s 43 …but oh dear – again there was something spare or leftover- No luck yet – 4 doesn’t work either —here 5 works! We have 26  many pieces after division !! So finally these all point at only 121 & 13 being factor numbers.

How to Find Factors of 131

The factors of any number can be found through any of the following methods and using those methods the factors of 131 can also be found. 

• Factors of 124 using the Multiplication Method
• Factors of 124 using the Division Method
• Prime Factorization of 124
• Factor tree of 124

Factors of 131 Using the Multiplication Method

To find the factors of 131, we can use a simple method called trial division.

• Start by trying to divide this number (131) by 1 and every other whole number until you reach it. Any time there is not a remainder left after dividing it will mean that a specific divisor is one of its factors!
•  For example, when divided by 1 we get 131 – which means 1 was able to perfectly fit into our original integer so it must be considered as one factor. As for 2, 3, or 4; they all leave remainders and thus are not included in possible answers leaving us with only five numbers being true potentials: 5,7,11, 13, and finally 131 itself!

Factors of 131 Using the Division Method

Let’s say we want to figure out the factors that make up a certain number, like 131. It can sound intimidating but it’s actually pretty easy – just follow a few simple steps!

1. Start with the number 1.
2. Divide 131 by 1: 131 ÷ 1 = 131. Since the division result is a whole number, 1 is a factor of 131.
3. Proceed to the next number, which is 2. Divide 131 by 2: 131 ÷ 2 = 65.5. Since the division result is not a whole number, 2 is not a factor of 131.
4. Continue this process for each subsequent number up to 131. However, since 131 is a prime number, it will only have two factors: 1 and 131.

Therefore, factors 131 are 1 and 131.

Prime Factorization of 131

If you want to figure out the prime factorization of a number like 131, it’s easy! Follow this process: First, write down your number (131). Next, divide that by the smallest possible prime number–2. When we do that calculation for 131 and 2…we get 65 with 1 remainder which tells us 2 isn’t a factor. Then try dividing 131 by 3; again our answer is 43 with 2 as its remainder which means 3 can’t be divided into it either. We will keep going up through larger and larger numbers until one gives us no remainders when divisible – in this case, 5 divided by 26 leaves behind only ONE left-over so BINGO 5 must be part of our “prime factors”. Basically what we’re doing here is breaking each big ‘number’ back down into small pieces made entirely from Prime Numbers leaving NO remains after they’ve all been combined together..like an intricate puzzle being put back together piece-by-piece!

Factor tree of 131

Prime factorization is an important Math skill that fifth graders need to master. To help with this, we can use a tool called a Factor Tree! Let’s take the number 131 and walk through how it works: 

• First, you write down your starting number – in our case; 131.
  Next up involve finding factors of your original number (1 & 3 are some of our options). You start by dividing your chosen figure firstly by 1 – if successful then 1 becomes one factor on the tree. 
• Afterwards Moving forward divide as many times as possible until there’s no remainder left when divided or all potential numbers have been checked- whichever comes first In this example131/3= 43r2 so three isn’t going to be part of what makes up 131– meaning continue searching for other factors utilizing larger values like 4 etc…

More Factors

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• Factors of 134

Factors of 131 – Quick Recap

• Factors of 131:  1, 131
• Negative Factors of 131:    -1, -131.
• Prime Factors of 131: 131
• Prime Factorization of 131:  131.

Solved Examples of Factor of 131

Q.1: How many sets of four factors of 131 are there?
Solution: The factors of 131 are 1 and 131 because 131 is a prime number. Since there are only two factors of 131, we cannot form a set of four factors.

Q.2: Lucas purchased a gift that cost $131. He paid with two $50 bills and the rest in coins. How much change did he receive?
Solution: Lucas received $21 in change ($50 + $50 = $100; $100 – $131 = -$31; -$31 + $21 = 0).

Q.3: Jane needs to divide 105 slices of pizza equally among 35 people. How many slices will each person get? 
Solution: Each person will get 3 slices of pizza (105 / 35 = 3).
 

Q.4: Rajiv wants to buy a car for exactly $131 dollars without using any coins or bills smaller than a dollar bill. How few bills can he use to pay for it? 
Solution: Rajiv can use two one-hundred-dollar bills ($100 + $100 = $200; $200 – $131 = 69 cents which are less than the smallest bill denomination) to buy the car for exactly $131 dollars without using any coins or bills smaller than a dollar bill.

Q.5: Joe needs to buy 18 items that cost six dollars each and five items that cost seven dollars each from a store that only accepts payment in multiples of seven dollars up to 25 dollars maximum per purchase transaction. How many transactions must Joe make to buy all 23 items? 
Solution: Joe must make three transactions in order to buy all 23 items (7 x 18 = 126; 7 x 5 = 35; 126 + 35 = 161; 161 / 7 = 23 remaining cents which is less than 25).

Q.6: Alice needs to divide 131 chocolate bars among 33 children evenly while making sure each child gets at least two bars but no more than four bars each time they turn around from her station distribution line. How many different methods can Alice use to achieve this task?  
Solution: There are 5 different methods Alice can use to divide the chocolate bars among the children evenly distributing at least two but no more than four bars per child turnaround/ visit from her station line(2 x 33=66; 4 x 16=64 leaving 1 bar leftover so 66+64+1=131 total bars ).

Q.7: If all prime numbers between 1 and 10 are multiplied together what will be a factor of the final product equal to 131? 
Solution: The number 37 will be a factor of the final product equal to 131 when all prime numbers between 1 and 10 are multiplied together( 2x3x5x7x11=2310; 2310/37= 62 remainders 1;2310+1=2311; 2311/37=62 ).

Q.8: Sarah has eight snacks that weigh 8 ounces or less apiece that she would like to place in boxes weighing 12 ounces or less altogether on her way home from work today but no single box should exceed 4 ounces when filled with individual snacks under any circumstances. Two half-ounce snacks were already placed into one box before Sarah reached her destination today. How many boxes does she need for all her snacks if none remain unboxed?   
Solution: Sarah needs five boxes for all her snacks since none remain unboxed(2+.5+.5=3 ounces per box initially, 4 -3 leftover ounce capacity still available, 8 total snacks need boxed/divided ) ( 8/4=2 remainder 0, 2 x 4 oz boxes needed plus 1 additional box left over with 0 leftover oz capacity after filling them up). 

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Frequently Asked Questions on Factors of 131